Tính \(\sqrt{\sqrt{28-16\sqrt{3}}}-\sqrt{\sqrt{28+16\sqrt{3}}}\)
\(\frac{\sqrt{4-2\sqrt{3}}}{\sqrt{28-16\sqrt{3}}}-\frac{\sqrt{4+2\sqrt{3}}}{\sqrt{28+16\sqrt{3}}}\)
tính
1.\(\sqrt{147}+\sqrt{54}-4\sqrt{27}\)
2.\(\sqrt{28}-4\sqrt{63}+7\sqrt{112}\)
3.\(\sqrt{49}-5\sqrt{28}+\dfrac{1}{2}\sqrt{63}\)
4.\(\left(2\sqrt{6}-4\sqrt{3}-\dfrac{1}{4}\sqrt{8}\right).3\sqrt{6}\)
5.(\(2\sqrt{1\dfrac{9}{16}}-5\sqrt{5\dfrac{1}{16}}\)):\(\sqrt{16}\)
6.\(\left(\sqrt{48}-3\sqrt{27}-\sqrt{147}\right):\sqrt{3}\)
7.\(\left(\sqrt{50}-3\sqrt{49}\right):\sqrt{2}-\sqrt{162}:\sqrt{2}\)
8.\(\left(2\sqrt{1\dfrac{9}{10}}-\sqrt{5\dfrac{1}{10}}\right):\sqrt{10}\)
9.\(2\sqrt{\dfrac{16}{3}}-3\sqrt{\dfrac{1}{27}}-6\sqrt{\dfrac{4}{75}}\)
10.\(2\sqrt{27}-6\sqrt{\dfrac{4}{3}}+\dfrac{3}{5}\sqrt{75}\)
11.\(\dfrac{\sqrt{18}}{\sqrt{2}}-\dfrac{\sqrt{12}}{\sqrt{3}}\)
12.\(\dfrac{\sqrt{27}}{\sqrt{3}}+\dfrac{\sqrt{98}}{\sqrt{2}}-\sqrt{175}:\sqrt{7}\)
13.\(\left(\dfrac{\sqrt{8}}{\sqrt{2}}-\dfrac{\sqrt{180}}{\sqrt{5}}\right).\sqrt{5}-\sqrt{\dfrac{81}{11}}.\sqrt{11}\)
14.\(\sqrt{8\sqrt{3}}-2\sqrt{25\sqrt{12}}+4\sqrt{\sqrt{192}}\)
15.\(\left(3\sqrt{2}-2\sqrt{3}\right)\left(3\sqrt{2}+2\sqrt{3}\right)\)
16.\(\left(1+\sqrt{5}-\sqrt{3}\right)\left(1+\sqrt{5}+\sqrt{3}\right)\)
Tính:
\(\left(\sqrt{\sqrt{7}+\sqrt{48}}-\sqrt{\sqrt{28-16\sqrt{3}}}\right).\sqrt{\sqrt{7+\sqrt{48}}}\)
Tính: \((\sqrt{\sqrt{7+\sqrt{48}}}-\sqrt{\sqrt{28-16\sqrt{3}}})\sqrt{\sqrt{7+\sqrt{48}}}\)
1. Tìm giá trị nhỏ nhất của M:
M = \(\sqrt{x+3-4\sqrt{x-1}}+\sqrt{x+15+8\sqrt{x-1}}\)
2. Rút gọn:
A= \(\sqrt{\sqrt{28-16\sqrt{3}}}-\sqrt{\sqrt{28+16\sqrt{3}}}\)
B= \(\sqrt{5-2\sqrt{2+\sqrt{9+4\sqrt{2}}}}\)
2.
A=\(\sqrt{\sqrt{\left(\sqrt{16}-\sqrt{12}\right)^2}}-\sqrt{\sqrt{\left(\sqrt{16}+\sqrt{12}\right)^2}}\)
\(=\sqrt{4-2\sqrt{3}}-\sqrt{4+2\sqrt{3}}\)
\(=\sqrt{\left(\sqrt{3}-\sqrt{1}\right)^2}-\sqrt{\left(\sqrt{3}+\sqrt{1}\right)^2}\)
\(=\sqrt{3}-1-\left(\sqrt{3}+1\right)\)
\(=\sqrt{3}-1-\sqrt{3}-1\)
\(=-2\)
B= \(\sqrt{5-2\sqrt{2+\sqrt{\left(\sqrt{8}+\sqrt{1}\right)^2}}}\)
\(=\sqrt{5-2\sqrt{2+\sqrt{8}+1}}\)
\(=\sqrt{5-2\sqrt{3+2\sqrt{2}}}\)
\(=\sqrt{5-2\sqrt{\left(\sqrt{2}+\sqrt{1}\right)^2}}\)
\(=\sqrt{5-2\sqrt{2}-2}\)
\(=\sqrt{3-2\sqrt{2}}\)
\(=\sqrt{\left(\sqrt{2}-\sqrt{1}\right)^2}\)
\(=\sqrt{2}-1\)
\(\left(\sqrt{\sqrt{7}+\sqrt{48}}-\sqrt{\sqrt{28-16\sqrt{3}}}\right).\sqrt{\sqrt{7}+\sqrt{48}}\)
\(\sqrt{28-16\sqrt{3}}+\sqrt{13-4\sqrt{3}}\)
\(\sqrt{28-16\sqrt{3}}+\sqrt{13-4\sqrt{3}}\)
\(=\sqrt{\left(4-2\sqrt{3}\right)^2}+\sqrt{\left(2\sqrt{3}-1\right)^2}\)
\(=\left|4-2\sqrt{3}\right|+\left|2\sqrt{3}-1\right|\)
\(=4-2\sqrt{3}+2\sqrt{3}-1=3\)
Rút gọn: \(\left(\sqrt{\sqrt{7}+\sqrt{48}}-\sqrt{\sqrt{28-16\sqrt{3}}}\right).\sqrt{\sqrt{7+\sqrt{48}}}\)
\(\sqrt{48}=4\sqrt{3}\) =>7+\(\sqrt{48}=7+4\sqrt{3}=\)(\(2+\sqrt{3}\))2
\(\sqrt{28-16\sqrt{3}}=2\sqrt{7-4\sqrt{3}}\)=2(2-\(\sqrt{3}\))=4-2\(\sqrt{3}\)=(\(\sqrt{3}-1\))2
viết lại biểu thức ta được
(\(\sqrt{\sqrt{7}+4\sqrt{3}}-\left(\sqrt{3}-1\right)\))(2+\(\sqrt{3}\))
Xem lại đề bài?
RG B=\(\left(\sqrt{\sqrt{7+\sqrt{48}}}-\sqrt{\sqrt{28-16\sqrt{3}}}\right)\cdot\sqrt{\sqrt{7+\sqrt{18}}}\)